What is the derivative of (x^9+7)/(x^9) ?

The derivative of (x^9+7)/(x^9) is -(63)/(x^{10)}

What is the first derivative of (x^9+7)/(x^9) ?

The first derivative of (x^9+7)/(x^9) is -(63)/(x^{10)}

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derivative of

\frac{x ^{9} + 7}{x ^{9}}

- \frac{63}{x ^{10}}

Solution steps

\frac{d}{d x} (\frac{x ^{9} + 7}{x ^{9}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{9} + 7 ) x ^{9} - \frac{d}{d x} ( x ^{9} ) ( x ^{9} + 7 )}{( x ^{9} ) ^{2}}

\frac{d}{d x} (x^{9} + 7) = 9 x^{8}

\frac{d}{d x} (x^{9}) = 9 x^{8}

= \frac{9 x ^{8} x ^{9} - 9 x ^{8} ( x ^{9} + 7 )}{( x ^{9} ) ^{2}}

Simplify

\frac{9 x ^{8} x ^{9} - 9 x ^{8} ( x ^{9} + 7 )}{( x ^{9} ) ^{2}} : - \frac{63}{x ^{10}}

= - \frac{63}{x ^{10}}

\frac{d}{d x} (1 0^{(x^{2} - 1)})

\int \frac{15 e ^{5 x}}{e ^{5 x} + 2} d x

f (x) = - 4 x^{2} + 7 x - 14, at x = - 2

\frac{\partial}{\partial x} (x^{c o s (x)})

e^{18 x}

What is the derivative of (x^9+7)/(x^9) ?
The derivative of (x^9+7)/(x^9) is -(63)/(x^{10)}
What is the first derivative of (x^9+7)/(x^9) ?
The first derivative of (x^9+7)/(x^9) is -(63)/(x^{10)}