What is the derivative of 4t^{1/2} ?

The derivative of 4t^{1/2} is 2/(t^{1/2)}

What is the first derivative of 4t^{1/2} ?

The first derivative of 4t^{1/2} is 2/(t^{1/2)}

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derivative of

4 t^{\frac{1}{2}}

\frac{2}{t ^{\frac{1}{2}}}

Solution steps

\frac{d}{d t} (4 t^{\frac{1}{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (t^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot \frac{1}{2} t^{\frac{1}{2} - 1}

Simplify

4 \cdot \frac{1}{2} t^{\frac{1}{2} - 1} : \frac{2}{t ^{\frac{1}{2}}}

= \frac{2}{t ^{\frac{1}{2}}}

4 - x^{2}, 2 - x

\frac{d}{d x} (16 x e^{- x})

\int - 3 x^{- 4} d x

x \to 1 + lim (x^{2} - 1)

\int_{0}^{1} 2 x (1 - x) d x

What is the derivative of 4t^{1/2} ?
The derivative of 4t^{1/2} is 2/(t^{1/2)}
What is the first derivative of 4t^{1/2} ?
The first derivative of 4t^{1/2} is 2/(t^{1/2)}