What is the tangent of f(x)=(5x)/(x+2),(3,3) ?

The tangent of f(x)=(5x)/(x+2),(3,3) is y= 2/5 x+9/5

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tangent of f(x)=(5x)/(x+2),(3,3)

tangent of

f (x) = \frac{5 x}{x + 2}, (3, 3)

y = \frac{2}{5} x + \frac{9}{5}

Solution steps

Find the slope of

f (x) = \frac{5 x}{x + 2} : \frac{df ( x )}{d x} = \frac{10}{( x + 2 ) ^{2}}

Compute the slope of

f (x) = \frac{5 x}{x + 2}

(3, 3) : m = \frac{2}{5}

Find the line with slope m=

\frac{2}{5}

and passing through

(3, 3) : y = \frac{2}{5} x + \frac{9}{5}

y = \frac{2}{5} x + \frac{9}{5}

\int_{0}^{4} \frac{x}{8} d x

f (x) = e^{x} - x e^{x}, at x = 0

x \to - 11 lim (x^{2} + 11)

x \to 0 lim (arctan (e^{x}))

\int_{2}^{3} \frac{1}{( x + 1 ) ln ( x + 1 )} d x

What is the tangent of f(x)=(5x)/(x+2),(3,3) ?
The tangent of f(x)=(5x)/(x+2),(3,3) is y= 2/5 x+9/5