What is the solution for y^{''}+4*y=cos(x) ?

The solution for y^{''}+4*y=cos(x) is y=c_{1}cos(2x)+c_{2}sin(2x)+1/3 cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+4*y=cos(x)

y^{^{''}} + 4 \cdot y = cos (x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{1}{3} cos (x)

Solution steps

y^{''} (x) + 4 \cdot y = cos (x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{1}{3} cos (x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{1}{3} cos (x)

\frac{d}{d x} (\frac{x}{x ^{2} + 225})

\int_{1}^{4} x^{2} - 5 x + 4 d x

x^{\frac{3}{2}} + x^{\frac{1}{2}}

x \to 1 lim (\frac{3 - x}{3 + x} e^{- x} cos (π x))

\frac{d}{d x} (\frac{8 x ^{2} + 6 x + 8}{x})

What is the solution for y^{''}+4*y=cos(x) ?
The solution for y^{''}+4*y=cos(x) is y=c_{1}cos(2x)+c_{2}sin(2x)+1/3 cos(x)