What is the derivative of 2^x-2x ?

The derivative of 2^x-2x is 2^xln(2)-2

What is the first derivative of 2^x-2x ?

The first derivative of 2^x-2x is 2^xln(2)-2

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\frac{d}{d x} (2^{x} - 2 x)

2^{x} ln (2) - 2

Solution steps

\frac{d}{d x} (2^{x} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2^{x}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d}{d x} (2 x) = 2

= 2^{x} ln (2) - 2

y = 2 x^{2}, y = 2 x + 6, - 2, 2

y \frac{d y}{d x} + 8 x^{3} = 4 x

\int tan (6 x) d x

\frac{d}{d x} (2 e^{x - 5})

y = - 9 x^{2}

What is the derivative of 2^x-2x ?
The derivative of 2^x-2x is 2^xln(2)-2
What is the first derivative of 2^x-2x ?
The first derivative of 2^x-2x is 2^xln(2)-2