What is the derivative of e^{x^2-x+1} ?

The derivative of e^{x^2-x+1} is e^{x^2-x+1}(2x-1)

What is the first derivative of e^{x^2-x+1} ?

The first derivative of e^{x^2-x+1} is e^{x^2-x+1}(2x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (e^{x^{2} - x + 1})

e^{x^{2} - x + 1} (2 x - 1)

Solution steps

\frac{d}{d x} (e^{x^{2} - x + 1})

Apply the chain rule:

e^{x^{2} - x + 1} \frac{d}{d x} (x^{2} - x + 1)

= e^{x^{2} - x + 1} \frac{d}{d x} (x^{2} - x + 1)

\frac{d}{d x} (x^{2} - x + 1) = 2 x - 1

= e^{x^{2} - x + 1} (2 x - 1)

\frac{d}{d x} (x^{4} + 4 x^{3} - 2 x^{2} - 12 x)

\frac{d}{d x} (1 0^{- 2 x})

\int \frac{x ^{2}}{2 x - 1} d x

\frac{8}{( 9 s ^{2} + 12 s + 4 ) ( s )}

\int x \cdot e^{x^{2}} d x

What is the derivative of e^{x^2-x+1} ?
The derivative of e^{x^2-x+1} is e^{x^2-x+1}(2x-1)
What is the first derivative of e^{x^2-x+1} ?
The first derivative of e^{x^2-x+1} is e^{x^2-x+1}(2x-1)