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Popular >

t^3y^'+4t^2y=0

Solution

t^{3} y^{^{'}} + 4 t^{2} y = 0

Solution

y = \frac{c _{1}}{t ^{4}}

Solution steps

t^{3} y^{'} (t) + 4 t^{2} y = 0

Solve separable ODE:

y = \frac{c _{1}}{t ^{4}}

y = \frac{c _{1}}{t ^{4}}

Popular Examples

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\int \frac{3 sin ^{3} ( x )}{cos ( x )} d x

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derivative of (2x+1/(x-3))

\frac{d}{d x} (\frac{2 x + 1}{x - 3})

derivative of sin(ln(3x^2+x))

\frac{d}{d x} (sin (ln (3 x^{2} + x)))

derivative of-(10/(10-x))

\frac{d}{d x} (- \frac{10}{10 - x})

Frequently Asked Questions (FAQ)

What is the solution for t^3y^'+4t^2y=0 ?
The solution for t^3y^'+4t^2y=0 is y=(c_{1})/(t^4)