What is (\partial)/(\partial b)(mx^b) ?

The answer to (\partial)/(\partial b)(mx^b) is mx^bln(x)

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(\partial)/(\partial b)(mx^b)

\frac{\partial}{\partial b} (m x^{b})

m x^{b} ln (x)

Solution steps

\frac{\partial}{\partial b} (m x^{b})

Treat

m, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= m \frac{\partial}{\partial b} (x^{b})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= m x^{b} ln (x)

\int 8 y d y

\int 4 sin (4 x) sin (3 x) cos (2 x) d x

\frac{\partial}{\partial x} (e^{- 3 y} cos (3 x))

t \to - \infty lim (e^{t} + 1)

\frac{d}{d x} (0.01 (0.2 x^{2} + 4 x + 64)^{\frac{2}{3}})

What is (\partial)/(\partial b)(mx^b) ?
The answer to (\partial)/(\partial b)(mx^b) is mx^bln(x)