What is the derivative of 3x^2+2x+4 ?

The derivative of 3x^2+2x+4 is 6x+2

What is the first derivative of 3x^2+2x+4 ?

The first derivative of 3x^2+2x+4 is 6x+2

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\frac{d}{d x} (3 x^{2} + 2 x + 4)

6 x + 2

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (4)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4) = 0

= 6 x + 2 + 0

Simplify

= 6 x + 2

\int_{0}^{2} \frac{1}{x ^{\frac{1}{3}}} d x

(x^{3})^{^{'}}

f (x) = x - 3

\int 2 x^{6} d x

\int e^{2} x cos (3 x) d x

What is the derivative of 3x^2+2x+4 ?
The derivative of 3x^2+2x+4 is 6x+2
What is the first derivative of 3x^2+2x+4 ?
The first derivative of 3x^2+2x+4 is 6x+2