What is the derivative of sqrt(8x-5) ?

The derivative of sqrt(8x-5) is 4/(sqrt(8x-5))

What is the first derivative of sqrt(8x-5) ?

The first derivative of sqrt(8x-5) is 4/(sqrt(8x-5))

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derivative of

8 x - 5

\frac{4}{8 x - 5}

Solution steps

\frac{d}{d x} (8 x - 5)

Apply the chain rule:

\frac{1}{2 8 x - 5} \frac{d}{d x} (8 x - 5)

= \frac{1}{2 8 x - 5} \frac{d}{d x} (8 x - 5)

\frac{d}{d x} (8 x - 5) = 8

= \frac{1}{2 8 x - 5} \cdot 8

Simplify

\frac{1}{2 8 x - 5} \cdot 8 : \frac{4}{8 x - 5}

= \frac{4}{8 x - 5}

\frac{d ^{4}}{d x ^{4}} (ln (1 + x))

y^{^{'}} + x = 0

\int 8 - 4 x - 4 x^{2} d x

x \to 0 lim (x^{2} + 4 x + 2)

n = 1 \sum \infty \frac{1}{ln ( n + 1 )}

What is the derivative of sqrt(8x-5) ?
The derivative of sqrt(8x-5) is 4/(sqrt(8x-5))
What is the first derivative of sqrt(8x-5) ?
The first derivative of sqrt(8x-5) is 4/(sqrt(8x-5))