What is (\partial)/(\partial y)(6xcos(x)cos(y)) ?

The answer to (\partial)/(\partial y)(6xcos(x)cos(y)) is -6xcos(x)sin(y)

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(\partial)/(\partial y)(6xcos(x)cos(y))

\frac{\partial}{\partial y} (6 x cos (x) cos (y))

- 6 x cos (x) sin (y)

Solution steps

\frac{\partial}{\partial y} (6 x cos (x) cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 x cos (x) \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= 6 x cos (x) (- sin (y))

Simplify

= - 6 x cos (x) sin (y)

y^{^{'}} + y = - x

x \to 0 lim \frac{( ( 6 + x ) ^{- 1} - 6 ^{- 1} )}{x}

f (x) = \frac{x ^{2} - 6 x + 12}{x - 4}

x^{2} - 3 x

\int_{0}^{3} \frac{1}{x ^{4}} d x

What is (\partial)/(\partial y)(6xcos(x)cos(y)) ?
The answer to (\partial)/(\partial y)(6xcos(x)cos(y)) is -6xcos(x)sin(y)