What is the tangent of f(x)=-(24)/((4x+1)),\at x=-1 ?

The tangent of f(x)=-(24)/((4x+1)),\at x=-1 is y= 32/3 x+56/3

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tangent of f(x)=-(24)/((4x+1)),\at x=-1

tangent of

f (x) = - \frac{24}{( 4 x + 1 )}, at x = - 1

y = \frac{32}{3} x + \frac{56}{3}

Solution steps

Find the tangent point:

(- 1, 8)

Find the slope of

f (x) = - \frac{24}{4 x + 1} : \frac{df ( x )}{d x} = \frac{96}{( 4 x + 1 ) ^{2}}

Compute the slope of

f (x) = - \frac{24}{4 x + 1}

x = - 1 : m = \frac{32}{3}

Find the line with slope m=

\frac{32}{3}

and passing through

(- 1, 8) : y = \frac{32}{3} x + \frac{56}{3}

y = \frac{32}{3} x + \frac{56}{3}

\frac{6 e ^{w}}{7 w}

\frac{d}{d x} (1 4^{2 x})

\frac{5 u}{4 u ^{2} + 1}

f (x) = x + 2, at x = 2

What is the tangent of f(x)=-(24)/((4x+1)),\at x=-1 ?
The tangent of f(x)=-(24)/((4x+1)),\at x=-1 is y= 32/3 x+56/3