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Popular >

y^{''}=-2/(t^2)

Solution

y^{^{''}} = - \frac{2}{t ^{2}}

Solution

y = 2 ln (t) + c_{1} t + c_{2}

Solution steps

y^{''} (t) = - \frac{2}{t ^{2}}

Solve

y^{''} (t) = - \frac{2}{t ^{2}} : y^{'} (t) = \frac{2}{t} + c_{1}

Solve

y^{'} (t) = \frac{2}{t} + c_{1} : y = 2 ln (t) + c_{1} t + c_{2}

y = 2 ln (t) + c_{1} t + c_{2}

Popular Examples

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y = x^{2} + 5 x + 9, at x = 4

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\frac{\partial}{\partial x} (yz e^{x z} + e^{x z} + x y e^{x z})

area y=1.2(x+0.1)^{0.5}+4,1,-0.1 area

y = 1.2 (x + 0.1)^{0.5} + 4, 1, - 0.1

sum from n=0 to infinity of 2^n2^n

n = 0 \sum \infty 2^{n} 2^{n}

(\partial)/(\partial z)(x^2y^2z^2)

\frac{\partial}{\partial z} (x^{2} y^{2} z^{2})

Frequently Asked Questions (FAQ)

What is the solution for y^{''}=-2/(t^2) ?
The solution for y^{''}=-2/(t^2) is y=2ln(t)+c_{1}t+c_{2}