What is the limit as x approaches 0 of ((x-4)/(x+1))^{x-2} ?

The limit as x approaches 0 of ((x-4)/(x+1))^{x-2} is 1/16

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limit as x approaches 0 of ((x-4)/(x+1))^{x-2}

x \to 0 lim ((\frac{x - 4}{x + 1})^{x - 2})

\frac{1}{16}

Decimal Notation

0.0625

Solution steps

x \to 0 lim ((\frac{x - 4}{x + 1})^{x - 2})

Plug in the value

x = 0

= (\frac{0 - 4}{0 + 1})^{0 - 2}

Simplify

(\frac{0 - 4}{0 + 1})^{0 - 2} : \frac{1}{16}

= \frac{1}{16}

\frac{d}{d x} (\frac{x x}{x ^{2}})

y^{^{'}} + 3 y = e^{- 4 t}, y (0) = 5

\frac{d}{d x} (\frac{9}{e ^{x} - e ^{- x}})

x^{2} + 3 y \frac{d y}{d x} = 0

\int_{0}^{16} \frac{1}{x} d x

What is the limit as x approaches 0 of ((x-4)/(x+1))^{x-2} ?
The limit as x approaches 0 of ((x-4)/(x+1))^{x-2} is 1/16