What is the integral from-infinity to 8 of xe^{x/4} ?

The integral from-infinity to 8 of xe^{x/4} is 16e^2

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integral from-infinity to 8 of xe^{x/4}

\int_{- \infty}^{8} x e^{\frac{x}{4}} d x

16 e^{2}

Decimal Notation

118.22489 \dots

Solution steps

\int_{- \infty}^{8} x e^{\frac{x}{4}} d x

Compute the indefinite integral:

\int x e^{\frac{x}{4}} d x = 4 e^{\frac{x}{4}} x - 16 e^{\frac{x}{4}} + C

Compute the boundaries:

\int_{- \infty}^{8} x e^{\frac{x}{4}} d x = 16 e^{2} - 0

= 16 e^{2} - 0

Simplify

= 16 e^{2}

f (x) = 2 x^{4} - 11 x^{2}, at x = 1

\int \frac{x}{2 x ^{2} + 3} d x

7 + e^{- 5 x} y^{^{'}} = 0

\int \frac{2 x - 1}{( x - 1 ) ( x - 2 )} d x

sin (w)

What is the integral from-infinity to 8 of xe^{x/4} ?
The integral from-infinity to 8 of xe^{x/4} is 16e^2