What is the derivative of 5\sqrt[3]{12x} ?

The derivative of 5\sqrt[3]{12x} is (5\sqrt[3]{4})/(3^{2/3)x^{2/3}}

What is the first derivative of 5\sqrt[3]{12x} ?

The first derivative of 5\sqrt[3]{12x} is (5\sqrt[3]{4})/(3^{2/3)x^{2/3}}

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Solution steps

Simplify

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

Simplify

\frac{d}{d x} (\frac{2 x ^{3} + 8}{x})

\frac{d}{d x} (8 x cos (x^{2}))

x \to 8 lim ({f (7) g (- 7)})

\int \frac{4 x ^{2} + 8}{2 x ^{2} + 1} d x

\int \frac{1}{x 25 x ^{2} - 4} d x

What is the derivative of 5\sqrt[3]{12x} ?
The derivative of 5\sqrt[3]{12x} is (5\sqrt[3]{4})/(3^{2/3)x^{2/3}}
What is the first derivative of 5\sqrt[3]{12x} ?
The first derivative of 5\sqrt[3]{12x} is (5\sqrt[3]{4})/(3^{2/3)x^{2/3}}