What is the sum from n=1 to infinity of (-3/4)^n ?

The sum from n=1 to infinity of (-3/4)^n is converges

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sum from n=1 to infinity of (-3/4)^n

n = 1 \sum \infty (- \frac{3}{4})^{n}

converges

Solution steps

n = 1 \sum \infty (- \frac{3}{4})^{n}

Apply Series Ratio Test:

converges

= converges

x \to 0 - lim (cos (x^{2}))

\int_{0}^{3} \frac{1}{4 - t} d t

\frac{\partial}{\partial x} (- z^{2})

f (x) = 5 x - 1

\int_{- 0.5}^{0} 1.5 x^{2} d x

What is the sum from n=1 to infinity of (-3/4)^n ?
The sum from n=1 to infinity of (-3/4)^n is converges