What is (\partial)/(\partial x)(cos(4y-3x)) ?

The answer to (\partial)/(\partial x)(cos(4y-3x)) is 3sin(4y-3x)

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(\partial)/(\partial x)(cos(4y-3x))

\frac{\partial}{\partial x} (cos (4 y - 3 x))

3 sin (4 y - 3 x)

Solution steps

\frac{\partial}{\partial x} (cos (4 y - 3 x))

Treat

y

as a constant

Apply the chain rule:

- sin (4 y - 3 x) \frac{\partial}{\partial x} (4 y - 3 x)

= - sin (4 y - 3 x) \frac{\partial}{\partial x} (4 y - 3 x)

\frac{\partial}{\partial x} (4 y - 3 x) = - 3

= - sin (4 y - 3 x) (- 3)

Simplify

= 3 sin (4 y - 3 x)

\int sin (x) tan^{2} (x) d x

\frac{\partial}{\partial x} (x^{2} - 2 x)

\int (x^{2} + x - 6) d x

\int \frac{x}{25 + 4 x ^{2}} d x

What is (\partial)/(\partial x)(cos(4y-3x)) ?
The answer to (\partial)/(\partial x)(cos(4y-3x)) is 3sin(4y-3x)