What is the solution for (dy)/(dx)+y= 1/(1+e^x) ?

The solution for (dy)/(dx)+y= 1/(1+e^x) is y=(ln(1+e^x))/(e^x)+(c_{1})/(e^x)

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(dy)/(dx)+y= 1/(1+e^x)

\frac{d y}{d x} + y = \frac{1}{1 + e ^{x}}

y = \frac{ln ( 1 + e ^{x} )}{e ^{x}} + \frac{c _{1}}{e ^{x}}

Solution steps

\frac{d y}{d x} + y = \frac{1}{1 + e ^{x}}

Solve linear ODE:

y = \frac{ln ( 1 + e ^{x} )}{e ^{x}} + \frac{c _{1}}{e ^{x}}

y = \frac{ln ( 1 + e ^{x} )}{e ^{x}} + \frac{c _{1}}{e ^{x}}

y = (x^{3} - 9 x)^{12}, (3, 0)

\frac{\partial}{\partial x} (3 y cos (- 3 x))

\frac{d}{d x} (x^{2} - x - 12)

tan (7) x^{2}

\int_{0}^{1} 2 - x^{2} d x

What is the solution for (dy)/(dx)+y= 1/(1+e^x) ?
The solution for (dy)/(dx)+y= 1/(1+e^x) is y=(ln(1+e^x))/(e^x)+(c_{1})/(e^x)