What is (\partial)/(\partial x)(7x^{6y}) ?

The answer to (\partial)/(\partial x)(7x^{6y}) is 42yx^{6y-1}

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(\partial)/(\partial x)(7x^{6y})

\frac{\partial}{\partial x} (7 x^{6 y})

42 y x^{6 y - 1}

Solution steps

\frac{\partial}{\partial x} (7 x^{6 y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{\partial}{\partial x} (x^{6 y})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 \cdot 6 y x^{6 y - 1}

Simplify

= 42 y x^{6 y - 1}

\frac{\partial}{\partial b} ((a x + b - y)^{2})

\int e^{\frac{- x}{3}} cos (5 x) d x

x \to 0 lim (\frac{11 sin ( 8 x )}{x})

7 y^{3} + 9 x^{8} = 5 y + 11 x, (1, 1)

x^{4} + 5 x^{2} - x

What is (\partial)/(\partial x)(7x^{6y}) ?
The answer to (\partial)/(\partial x)(7x^{6y}) is 42yx^{6y-1}