What is the solution for derivative of y=(sin(x/2)-cos(x/2))^2 ?

The solution for derivative of y=(sin(x/2)-cos(x/2))^2 is y=cos(x)+x+c_{1}

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derivative of y=(sin(x/2)-cos(x/2))^2

\frac{d}{d x} y = (sin (\frac{x}{2}) - cos (\frac{x}{2}))^{2}

y = cos (x) + x + c_{1}

Solution steps

\frac{d y}{d x} = (sin (\frac{x}{2}) - cos (\frac{x}{2}))^{2}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (sin (\frac{x}{2}) - cos (\frac{x}{2}))^{2} d x

\int (sin (\frac{x}{2}) - cos (\frac{x}{2}))^{2} d x = cos (x) + x + c_{1}

y = cos (x) + x + c_{1}

\int \frac{5 - x}{2 x ^{2} + x - 1} d x

\frac{\partial}{\partial x} (a r cot (\frac{y}{x}))

y = e^{2 e^{x}}

x \to 3 lim (x^{2} - x - 6)

What is the solution for derivative of y=(sin(x/2)-cos(x/2))^2 ?
The solution for derivative of y=(sin(x/2)-cos(x/2))^2 is y=cos(x)+x+c_{1}