What is the first derivative of 1^2 ?

The first derivative of 1^2 is 0

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derivative of 1^2

\frac{d}{d x} (1^{2})

0

Solution steps

\frac{d}{d x} (1^{2})

1^{2} = 1

= \frac{d}{d x} (1)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\int 2 x e^{y} + 2 x y^{- 1} + y^{- 3}

\frac{- 2 s + 6}{s ^{2} + 4}

x \to 2 lim (ln (\frac{x}{x - 2}))

y^{'} = 3 y \cdot (y - 2)

x \to π lim (\frac{sin ( x )}{1 - \frac{x ^{2}}{π ^{2}}})