What is the solution for y^{''}+4y^'=0,y(0)=1 ?

The solution for y^{''}+4y^'=0,y(0)=1 is y=1-c_{2}+c_{2}e^{-4t}

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y^{''}+4y^'=0,y(0)=1

y^{^{''}} + 4 y^{^{'}} = 0, y (0) = 1

y = 1 - c_{2} + c_{2} e^{- 4 t}

Solution steps

y^{''} (t) + 4 y^{'} (t) = 0

Solve linear ODE:

y = 1 - c_{2} + c_{2} e^{- 4 t}

y = 1 - c_{2} + c_{2} e^{- 4 t}

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What is the solution for y^{''}+4y^'=0,y(0)=1 ?
The solution for y^{''}+4y^'=0,y(0)=1 is y=1-c_{2}+c_{2}e^{-4t}