What is the sum from n=1 to infinity of ((3^n))/(n!) ?

The sum from n=1 to infinity of ((3^n))/(n!) is converges

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sum from n=1 to infinity of ((3^n))/(n!)

n = 1 \sum \infty \frac{( 3 ^{n} )}{n !}

converges

Solution steps

n = 1 \sum \infty \frac{3 ^{n}}{n !}

Apply Series Ratio Test:

converges

= converges

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What is the sum from n=1 to infinity of ((3^n))/(n!) ?
The sum from n=1 to infinity of ((3^n))/(n!) is converges