What is (\partial)/(\partial z)(-xyz^2) ?

The answer to (\partial)/(\partial z)(-xyz^2) is -2xyz

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(\partial)/(\partial z)(-xyz^2)

\frac{\partial}{\partial z} (- x y z^{2})

- 2 x yz

Solution steps

\frac{\partial}{\partial z} (- x y z^{2})

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - x y \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - x y \cdot 2 z^{2 - 1}

Simplify

= - 2 x yz

\int 7 sec^{3} (3 x) d x

\int (\frac{8}{3} + 4 u^{2}) d u

\frac{d ^{2}}{d x ^{2}} (1 + x)

What is (\partial)/(\partial z)(-xyz^2) ?
The answer to (\partial)/(\partial z)(-xyz^2) is -2xyz