What is the solution for -9x^2y+(dy)/(dx)=-2x^2 ?

The solution for -9x^2y+(dy)/(dx)=-2x^2 is y=(e^{3x^3+c_{1}})/9+2/9

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-9x^2y+(dy)/(dx)=-2x^2

- 9 x^{2} y + \frac{d y}{d x} = - 2 x^{2}

y = \frac{e ^{3 x^{3} + c_{1}}}{9} + \frac{2}{9}

Solution steps

- 9 x^{2} y + \frac{d y}{d x} = - 2 x^{2}

Solve separable ODE:

y = \frac{e ^{3 x^{3} + c_{1}}}{9} + \frac{2}{9}

y = \frac{e ^{3 x^{3} + c_{1}}}{9} + \frac{2}{9}

\frac{( 2 x + 1 )}{x - 4}

\frac{d}{d x} (cos^{3} (1 - 5 x^{2}))

y = arcsin (5 x)

\frac{6 x}{1 - cot ( x )}

\int \frac{( x + 1 ) ^{3}}{( x ) ^{10}} d x

What is the solution for -9x^2y+(dy)/(dx)=-2x^2 ?
The solution for -9x^2y+(dy)/(dx)=-2x^2 is y=(e^{3x^3+c_{1}})/9+2/9