What is the derivative of sec(x)-6cos(x) ?

The derivative of sec(x)-6cos(x) is sec(x)tan(x)+6sin(x)

What is the first derivative of sec(x)-6cos(x) ?

The first derivative of sec(x)-6cos(x) is sec(x)tan(x)+6sin(x)

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derivative of

sec (x) - 6 cos (x)

sec (x) tan (x) + 6 sin (x)

Solution steps

\frac{d}{d x} (sec (x) - 6 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sec (x)) - \frac{d}{d x} (6 cos (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

\frac{d}{d x} (6 cos (x)) = - 6 sin (x)

= sec (x) tan (x) - (- 6 sin (x))

Simplify

= sec (x) tan (x) + 6 sin (x)

\frac{\partial}{\partial y} (x^{y} - x y)

\frac{d y}{d x} = 2 x e^{y}

\frac{d}{d x} ((3 x)^{3 x})

\int \frac{1}{a + b x} d x

\frac{d}{d x} (- 4 cot (2 x) csc (2 x))

What is the derivative of sec(x)-6cos(x) ?
The derivative of sec(x)-6cos(x) is sec(x)tan(x)+6sin(x)
What is the first derivative of sec(x)-6cos(x) ?
The first derivative of sec(x)-6cos(x) is sec(x)tan(x)+6sin(x)