What is area y=-x^2-8x-12,y=0,[-4,-1] ?

The answer to area y=-x^2-8x-12,y=0,[-4,-1] is 23/3

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area y=-x^2-8x-12,y=0,[-4,-1]

area

y = - x^{2} - 8 x - 12, y = 0, [- 4, - 1]

\frac{23}{3}

Decimal Notation

7.66666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{- 1} x^{2} + 8 x + 12 d x

Solve

\int_{- 4}^{- 1} x^{2} + 8 x + 12 d x : \frac{23}{3}

The area is:

= \frac{23}{3}

f (x) = e^{- 8 x}

\int_{0}^{3} x^{2} - 6 d x

\int_{0}^{π} 13 sin^{2} (4 x) d x

\frac{( s + 1 )}{( s ^{2} + s - 1 )}

(\frac{d y}{d x}) + \frac{1}{y} = \frac{y}{2} + \frac{x}{y}

What is area y=-x^2-8x-12,y=0,[-4,-1] ?
The answer to area y=-x^2-8x-12,y=0,[-4,-1] is 23/3