What is the derivative of 6x^3-9x+4 ?

The derivative of 6x^3-9x+4 is 18x^2-9

What is the first derivative of 6x^3-9x+4 ?

The first derivative of 6x^3-9x+4 is 18x^2-9

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\frac{d}{d x} (6 x^{3} - 9 x + 4)

18 x^{2} - 9

Solution steps

\frac{d}{d x} (6 x^{3} - 9 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{3}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (4)

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (4) = 0

= 18 x^{2} - 9 + 0

Simplify

= 18 x^{2} - 9

x \to - 1 lim (4)

\frac{\partial}{\partial x} (f (y, x) (\frac{y}{x}))

n = 1 \sum \infty \frac{( - 1 ) ^{6 n}}{n}

\frac{\partial}{\partial x} (30 y^{2} x)

\int - 3 x^{2} cos (x^{3}) d x

What is the derivative of 6x^3-9x+4 ?
The derivative of 6x^3-9x+4 is 18x^2-9
What is the first derivative of 6x^3-9x+4 ?
The first derivative of 6x^3-9x+4 is 18x^2-9