What is (\partial)/(\partial x)(sin(3x-2y)) ?

The answer to (\partial)/(\partial x)(sin(3x-2y)) is cos(3x-2y)*3

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(\partial)/(\partial x)(sin(3x-2y))

\frac{\partial}{\partial x} (sin (3 x - 2 y))

cos (3 x - 2 y) \cdot 3

Solution steps

\frac{\partial}{\partial x} (sin (3 x - 2 y))

Treat

y

as a constant

Apply the chain rule:

cos (3 x - 2 y) \frac{\partial}{\partial x} (3 x - 2 y)

= cos (3 x - 2 y) \frac{\partial}{\partial x} (3 x - 2 y)

\frac{\partial}{\partial x} (3 x - 2 y) = 3

= cos (3 x - 2 y) \cdot 3

\frac{d}{d x} (ln (x^{2} - x))

y = - 3 cos (x), at x = \frac{- π}{3}

(e^{y} + 1)^{2} e^{- y} d x + (e^{x} + 1)^{3} d y = 0

\int 4 e^{x} + 12 x^{3} + 4 x d x

f (x) = 2 sin (x), at x = \frac{π}{4}

What is (\partial)/(\partial x)(sin(3x-2y)) ?
The answer to (\partial)/(\partial x)(sin(3x-2y)) is cos(3x-2y)*3