What is the d/(dθ)(sin(4θ)) ?

The d/(dθ)(sin(4θ)) is cos(4θ)*4

What is the first d/(dθ)(sin(4θ)) ?

The first d/(dθ)(sin(4θ)) is cos(4θ)*4

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\frac{d}{d θ} (sin (4 θ))

cos (4 θ) \cdot 4

Solution steps

\frac{d}{d θ} (sin (4 θ))

Apply the chain rule:

cos (4 θ) \frac{d}{d θ} (4 θ)

= cos (4 θ) \frac{d}{d θ} (4 θ)

\frac{d}{d θ} (4 θ) = 4

= cos (4 θ) \cdot 4

\int x (x^{2} - 2) d x

(f (t) \circ g (t))^{'}

\int_{2}^{3} \frac{x + 1}{x ^{2} - x} d x

x \to 1 lim (\frac{3 x + 2}{4 x - 5})

\frac{\partial}{\partial x} (10 - (3 x^{2} + 3 y^{2}))