What is the derivative of (x^4-3x)^2 ?

The derivative of (x^4-3x)^2 is 2(x^4-3x)(4x^3-3)

What is the first derivative of (x^4-3x)^2 ?

The first derivative of (x^4-3x)^2 is 2(x^4-3x)(4x^3-3)

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derivative of

(x^{4} - 3 x)^{2}

2 (x^{4} - 3 x) (4 x^{3} - 3)

Solution steps

\frac{d}{d x} ((x^{4} - 3 x)^{2})

Apply the chain rule:

2 (x^{4} - 3 x) \frac{d}{d x} (x^{4} - 3 x)

= 2 (x^{4} - 3 x) \frac{d}{d x} (x^{4} - 3 x)

\frac{d}{d x} (x^{4} - 3 x) = 4 x^{3} - 3

= 2 (x^{4} - 3 x) (4 x^{3} - 3)

13 x

\int \frac{2 x}{e ^{8 x}} d x

y = - 3 x^{2} - x

\frac{d ^{2}}{d x ^{2}} (\frac{1}{ln ( x )})

\frac{d}{d y} (y^{2})

What is the derivative of (x^4-3x)^2 ?
The derivative of (x^4-3x)^2 is 2(x^4-3x)(4x^3-3)
What is the first derivative of (x^4-3x)^2 ?
The first derivative of (x^4-3x)^2 is 2(x^4-3x)(4x^3-3)