What is the integral of 3/(x^2)-2/(x^3) ?

The integral of 3/(x^2)-2/(x^3) is -3/x+1/(x^2)+C

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integral of 3/(x^2)-2/(x^3)

\int \frac{3}{x ^{2}} - \frac{2}{x ^{3}} d x

- \frac{3}{x} + \frac{1}{x ^{2}} + C

Solution steps

\int \frac{3}{x ^{2}} - \frac{2}{x ^{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3}{x ^{2}} d x - \int \frac{2}{x ^{3}} d x

\int \frac{3}{x ^{2}} d x = - \frac{3}{x}

\int \frac{2}{x ^{3}} d x = - \frac{1}{x ^{2}}

= - \frac{3}{x} - (- \frac{1}{x ^{2}})

Simplify

= - \frac{3}{x} + \frac{1}{x ^{2}}

Add a constant to the solution

= - \frac{3}{x} + \frac{1}{x ^{2}} + C

x^{3}

\frac{d}{d x} (ln (x) e^{x})

\frac{d}{d x} ((5 x - 4)^{2})

f (x) = ln (\frac{1}{x})

\frac{d y}{d t} = y - 2 t

What is the integral of 3/(x^2)-2/(x^3) ?
The integral of 3/(x^2)-2/(x^3) is -3/x+1/(x^2)+C