What is volumeabout y=0,y=sqrt(x),[0,1] ?

The answer to volumeabout y=0,y=sqrt(x),[0,1] is pi/2

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volumeabout y=0,y=sqrt(x),[0,1]

volume about

y = 0, y = x, [0, 1]

\frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

Apply the volume formula:

\int_{0}^{1} π x d x

Solve

\int_{0}^{1} π x d x : \frac{π}{2}

The volume for solid of revolution is:

= \frac{π}{2}

f (x) = \frac{5}{x + 4}

\int_{0}^{t} t^{2} e^{- \frac{t}{4}} d t

\int (x + 6) (3 x - 4) d x

\int_{- 2}^{0} 3 x 4 - x^{2} d x

\frac{\partial}{\partial x} (ln (2 + x^{2} + y^{2}))

What is volumeabout y=0,y=sqrt(x),[0,1] ?
The answer to volumeabout y=0,y=sqrt(x),[0,1] is pi/2