What is the integral from 0 to 1 of x^3 ?

The integral from 0 to 1 of x^3 is 1/4

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integral from 0 to 1 of x^3

\int_{0}^{1} x^{3} d x

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\int_{0}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{1}

= [\frac{x ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= \frac{1}{4}

\frac{d}{d x} (\frac{3}{x ( x ^{2} - 4 )})

x y - 2 y^{2} = 3

\frac{\partial}{\partial x} (6 y^{\frac{x}{z}})

sec (x) d y = x cot (y) d x

\int \frac{( x ^{2} + 1 )}{e ^{x}} d x

What is the integral from 0 to 1 of x^3 ?
The integral from 0 to 1 of x^3 is 1/4