What is (\partial ^2)/(\partial x^2)(sin^2(mx+ny)) ?

The answer to (\partial ^2)/(\partial x^2)(sin^2(mx+ny)) is 2m^2cos(2(mx+ny))

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(\partial ^2)/(\partial x^2)(sin^2(mx+ny))

\frac{\partial ^{2}}{\partial x ^{2}} (sin^{2} (m x + n y))

2 m^{2} cos (2 (m x + n y))

Solution steps

\frac{\partial ^{2}}{\partial x ^{2}} (sin^{2} (m x + n y))

\frac{\partial}{\partial x} (sin^{2} (m x + n y)) = m sin (2 (m x + n y))

= \frac{\partial}{\partial x} (m sin (2 (m x + n y)))

\frac{\partial}{\partial x} (m sin (2 (m x + n y))) = 2 m^{2} cos (2 (m x + n y))

= 2 m^{2} cos (2 (m x + n y))

\frac{1}{( s - 1 ) ^{5}}

\frac{d}{d x} (2 x^{3} - 5 x)

\int \frac{2}{( x - 2 ) ^{2}} d x

x = y^{2} - 8, x = 8

\int (\frac{x + 4}{x}) d x

What is (\partial ^2)/(\partial x^2)(sin^2(mx+ny)) ?
The answer to (\partial ^2)/(\partial x^2)(sin^2(mx+ny)) is 2m^2cos(2(mx+ny))