What is the derivative of y=tan(e^x) ?

The derivative of y=tan(e^x) is sec^2(e^x)e^x

What is the first derivative of y=tan(e^x) ?

The first derivative of y=tan(e^x) is sec^2(e^x)e^x

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derivative of

y = tan (e^{x})

sec^{2} (e^{x}) e^{x}

Solution steps

\frac{d}{d x} (tan (e^{x}))

Apply the chain rule:

sec^{2} (e^{x}) \frac{d}{d x} (e^{x})

= sec^{2} (e^{x}) \frac{d}{d x} (e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

= sec^{2} (e^{x}) e^{x}

\int_{3}^{4} x^{2} d x

\frac{d}{d x} (\frac{5 x + 1}{2 x})

e^{3 - t}

\frac{d}{d x} (\frac{- y ^{2}}{( x - y ) ^{2}})

\frac{\partial ^{2}}{\partial x ^{2}} (sin^{2} (m x + n y))

What is the derivative of y=tan(e^x) ?
The derivative of y=tan(e^x) is sec^2(e^x)e^x
What is the first derivative of y=tan(e^x) ?
The first derivative of y=tan(e^x) is sec^2(e^x)e^x