What is the derivative of 2sec(2x) ?

The derivative of 2sec(2x) is 4sec(2x)tan(2x)

What is the first derivative of 2sec(2x) ?

The first derivative of 2sec(2x) is 4sec(2x)tan(2x)

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derivative of

2 sec (2 x)

4 sec (2 x) tan (2 x)

Solution steps

\frac{d}{d x} (2 sec (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sec (2 x))

Apply the chain rule:

sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

= sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 sec (2 x) tan (2 x) \cdot 2

Simplify

= 4 sec (2 x) tan (2 x)

n = 1 \sum \infty lo g_{e} (\frac{n}{n + 1})

x \to 0 lim (\frac{1}{x - x ^{2}} - \frac{1}{x})

\frac{d}{d x} (1 + \frac{9}{4} x)

\frac{d}{d x} ((3 - 5 x e^{x}) (3 x + 2))

\int x sin (11 x) d x

What is the derivative of 2sec(2x) ?
The derivative of 2sec(2x) is 4sec(2x)tan(2x)
What is the first derivative of 2sec(2x) ?
The first derivative of 2sec(2x) is 4sec(2x)tan(2x)