What is the limit as h approaches 0 of (cos(pi/6+h)-(sqrt(3))/2)/(h) ?

The limit as h approaches 0 of (cos(pi/6+h)-(sqrt(3))/2)/(h) is -1/2

Popular >

limit as h approaches 0 of (cos(pi/6+h)-(sqrt(3))/2)/(h)

h \to 0 lim (\frac{cos ( \frac{π}{6} + h ) - \frac{3}{2}}{h})

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

h \to 0 lim (\frac{cos ( \frac{π}{6} + h ) - \frac{3}{2}}{h})

Apply L'Hopital's Rule

: h \to 0 lim (\frac{- sin ( h + \frac{π}{6} )}{1})

= h \to 0 lim (\frac{- sin ( h + \frac{π}{6} )}{1})

Plug in the value

h = 0

= \frac{- sin ( 0 + \frac{π}{6} )}{1}

Simplify

\frac{- sin ( 0 + \frac{π}{6} )}{1} : - \frac{1}{2}

= - \frac{1}{2}

\int \frac{ln ( x ) + 1}{x ln ( x )} d x

\int 19 sin^{2} (x) cos^{3} (x) d x

\int \frac{x - 3}{x ^{2} - 7 x - 18} d x

\frac{\partial}{\partial x} (- 6 e^{6 y} sin (6 x))

What is the limit as h approaches 0 of (cos(pi/6+h)-(sqrt(3))/2)/(h) ?
The limit as h approaches 0 of (cos(pi/6+h)-(sqrt(3))/2)/(h) is -1/2