What is (\partial)/(\partial x)(9x^2+y^2) ?

The answer to (\partial)/(\partial x)(9x^2+y^2) is 18x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(9x^2+y^2)

\frac{\partial}{\partial x} (9 x^{2} + y^{2})

18 x

Solution steps

\frac{\partial}{\partial x} (9 x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9 x^{2}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (9 x^{2}) = 18 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 18 x + 0

Simplify

= 18 x

\int e^{x^{2}} d x

\frac{\partial}{\partial x} (\frac{x + 5}{y + 2})

\int \frac{1}{8 x ^{3}} d x

\int \frac{x ^{5} - x + 2}{x ^{2} - x} d x

What is (\partial)/(\partial x)(9x^2+y^2) ?
The answer to (\partial)/(\partial x)(9x^2+y^2) is 18x