What is the derivative of e^{-2x}sin(2x) ?

The derivative of e^{-2x}sin(2x) is -2e^{-2x}sin(2x)+2e^{-2x}cos(2x)

What is the first derivative of e^{-2x}sin(2x) ?

The first derivative of e^{-2x}sin(2x) is -2e^{-2x}sin(2x)+2e^{-2x}cos(2x)

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\frac{d}{d x} (e^{- 2 x} sin (2 x))

- 2 e^{- 2 x} sin (2 x) + 2 e^{- 2 x} cos (2 x)

Solution steps

\frac{d}{d x} (e^{- 2 x} sin (2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{- 2 x}, g = sin (2 x)

= \frac{d}{d x} (e^{- 2 x}) sin (2 x) + \frac{d}{d x} (sin (2 x)) e^{- 2 x}

\frac{d}{d x} (e^{- 2 x}) = - 2 e^{- 2 x}

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= (- 2 e^{- 2 x}) sin (2 x) + cos (2 x) \cdot 2 e^{- 2 x}

Simplify

= - 2 e^{- 2 x} sin (2 x) + 2 e^{- 2 x} cos (2 x)

\int_{0}^{1} \frac{1}{x ^{1.5}} d x

y = x + 1

\int 7 x^{2} e^{2 x} d x

x \to - 5 lim (\frac{5 x + 4}{x + 8})

(\frac{1}{y ^{2}} - \frac{7}{y ^{4}}) (y - 5 y^{3})

What is the derivative of e^{-2x}sin(2x) ?
The derivative of e^{-2x}sin(2x) is -2e^{-2x}sin(2x)+2e^{-2x}cos(2x)
What is the first derivative of e^{-2x}sin(2x) ?
The first derivative of e^{-2x}sin(2x) is -2e^{-2x}sin(2x)+2e^{-2x}cos(2x)