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Popular >

y^'=sqrt(1-y^2)

Solution

y^{^{'}} = 1 - y^{2}

Solution

y = sin (t + c_{1})

Solution steps

y^{'} (t) = 1 - y^{2}

Solve separable ODE:

y = sin (t + c_{1})

y = sin (t + c_{1})

Popular Examples

derivative of (2x-7)^4(x^2+x+1)^5 derivative of

(2 x - 7)^{4} (x^{2} + x + 1)^{5}

derivative of (9z^4+3z^2+1)(3z^3-z)derivative of

(9 z^{4} + 3 z^{2} + 1) (3 z^{3} - z)

y^'=8x+y,y(0)=4

y^{^{'}} = 8 x + y, y (0) = 4

(\partial)/(\partial t)(ae^{kx+wt})

\frac{\partial}{\partial t} (a e^{k x + wt})

integral of f(x)g(x)

\int f (x) g (x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=sqrt(1-y^2) ?
The solution for y^'=sqrt(1-y^2) is y=sin(t+c_{1})