What is the integral of (6sqrt(x)-\sqrt[6]{x}) ?

The integral of (6sqrt(x)-\sqrt[6]{x}) is 4x^{3/2}-6/7 x^{7/6}+C

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integral of (6sqrt(x)-\sqrt[6]{x})

4 x^{\frac{3}{2}} - \frac{6}{7} x^{\frac{7}{6}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 6 x d x = 4 x^{\frac{3}{2}}

= 4 x^{\frac{3}{2}} - \frac{6}{7} x^{\frac{7}{6}}

Add a constant to the solution

= 4 x^{\frac{3}{2}} - \frac{6}{7} x^{\frac{7}{6}} + C

y^{^{''}} = k^{2} y

\frac{d}{d x} (\frac{1 - x}{2 + x})

\frac{d}{d x} ((x + e^{2 x})^{3})

\int (sec (x))^{3} d x

\frac{7 x}{2 ^{x}}

What is the integral of (6sqrt(x)-\sqrt[6]{x}) ?
The integral of (6sqrt(x)-\sqrt[6]{x}) is 4x^{3/2}-6/7 x^{7/6}+C