What is the derivative of (2x^2+1)^2 ?

The derivative of (2x^2+1)^2 is 8x(2x^2+1)

What is the first derivative of (2x^2+1)^2 ?

The first derivative of (2x^2+1)^2 is 8x(2x^2+1)

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derivative of

(2 x^{2} + 1)^{2}

8 x (2 x^{2} + 1)

Solution steps

\frac{d}{d x} ((2 x^{2} + 1)^{2})

Apply the chain rule:

2 (2 x^{2} + 1) \frac{d}{d x} (2 x^{2} + 1)

= 2 (2 x^{2} + 1) \frac{d}{d x} (2 x^{2} + 1)

\frac{d}{d x} (2 x^{2} + 1) = 4 x

= 2 (2 x^{2} + 1) \cdot 4 x

Simplify

= 8 x (2 x^{2} + 1)

y^{^{'}} + 6 y = 0

\frac{\partial}{\partial y} (x sin (x) + y sin (y))

y^{^{''}} = k^{2} y

\frac{d}{d x} (\frac{1 - x}{2 + x})

What is the derivative of (2x^2+1)^2 ?
The derivative of (2x^2+1)^2 is 8x(2x^2+1)
What is the first derivative of (2x^2+1)^2 ?
The first derivative of (2x^2+1)^2 is 8x(2x^2+1)