What is the integral of (-2)/(1+x^2) ?

The integral of (-2)/(1+x^2) is -2arctan(x)+C

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integral of (-2)/(1+x^2)

\int \frac{- 2}{1 + x ^{2}} d x

- 2 arctan (x) + C

Solution steps

\int \frac{- 2}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= - 2 arctan (x)

Add a constant to the solution

= - 2 arctan (x) + C

f (x) = 9 ln (9 + 2 x^{2})

\int cos^{6} (θ) d θ

\frac{d}{d x} (3 - 4 x^{2})

f (x) = (x - x^{3}), at x = 1

\frac{d}{d x} (\frac{1}{4} e^{2 x})

What is the integral of (-2)/(1+x^2) ?
The integral of (-2)/(1+x^2) is -2arctan(x)+C