What is the limit as x approaches-1 of 2/((2x+2)^2) ?

The limit as x approaches-1 of 2/((2x+2)^2) is infinity

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limit as x approaches-1 of 2/((2x+2)^2)

x \to - 1 lim (\frac{2}{( 2 x + 2 ) ^{2}})

\infty

Solution steps

x \to - 1 lim (\frac{2}{( 2 x + 2 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 1 - lim (\frac{2}{( 2 x + 2 ) ^{2}}) = \infty

x \to - 1 + lim (\frac{2}{( 2 x + 2 ) ^{2}}) = \infty

= \infty

f (x) = \frac{x}{x + \frac{b}{x}}

f (x) = - 2 cos (x), at x = - π

\frac{\partial}{\partial y} (2 x yz)

\int \frac{sec ( x ) tan ( x )}{tan ( x )} d x

x + 1

What is the limit as x approaches-1 of 2/((2x+2)^2) ?
The limit as x approaches-1 of 2/((2x+2)^2) is infinity