What is the integral of (26x+4)/((5x+1)(x-1)) ?

The integral of (26x+4)/((5x+1)(x-1)) is 1/5 ln|5x+1|+5ln|x-1|+C

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integral of (26x+4)/((5x+1)(x-1))

\int \frac{26 x + 4}{( 5 x + 1 ) ( x - 1 )} d x

\frac{1}{5} ln ∣ 5 x + 1 ∣ + 5 ln ∣ x - 1 ∣ + C

Solution steps

\int \frac{26 x + 4}{( 5 x + 1 ) ( x - 1 )} d x

Take the partial fraction of

\frac{26 x + 4}{( 5 x + 1 ) ( x - 1 )} : \frac{1}{5 x + 1} + \frac{5}{x - 1}

= \int \frac{1}{5 x + 1} + \frac{5}{x - 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{5 x + 1} d x + \int \frac{5}{x - 1} d x

\int \frac{1}{5 x + 1} d x = \frac{1}{5} ln ∣ 5 x + 1 ∣

\int \frac{5}{x - 1} d x = 5 ln ∣ x - 1 ∣

= \frac{1}{5} ln ∣ 5 x + 1 ∣ + 5 ln ∣ x - 1 ∣

Add a constant to the solution

= \frac{1}{5} ln ∣ 5 x + 1 ∣ + 5 ln ∣ x - 1 ∣ + C

f (x) = \frac{1}{4} x^{4}

\frac{\partial}{\partial x} (e^{- x} sin (y))

\frac{\partial}{\partial x} (6 y^{8} x^{5} + 49 y x^{6})

y^{^{'}} = 8 + 2 x - 3 x^{2}

arcsec (x)

What is the integral of (26x+4)/((5x+1)(x-1)) ?
The integral of (26x+4)/((5x+1)(x-1)) is 1/5 ln|5x+1|+5ln|x-1|+C