What is the tangent of 5e^x ?

The tangent of 5e^x is y=5e^{a_{0}}x+5e^{a_{0}}-5e^{a_{0}}a_{0}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 5e^x

tangent of

5 e^{x}

y = 5 e^{a_{0}} x + 5 e^{a_{0}} - 5 e^{a_{0}} a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 5 e^{a_{0}})

Find the slope of

y = 5 e^{x} : \frac{d y}{d x} = 5 e^{x}

Compute the slope of

y = 5 e^{x}

x = a_{0} : m = 5 e^{a_{0}}

Find the line with slope m=

5 e^{a_{0}}

and passing through

(a_{0}, 5 e^{a_{0}}) : y = 5 e^{a_{0}} x + 5 e^{a_{0}} - 5 e^{a_{0}} a_{0}

y = 5 e^{a_{0}} x + 5 e^{a_{0}} - 5 e^{a_{0}} a_{0}

\int 2 x (- e^{- x}) d x

y = 3 x^{2} + 3, (2, 15)

\frac{\partial}{\partial x} (e^{k x - m t})

\frac{d}{d x} (x^{2} arctan (8 x))

\int 9 cos (t) d t

What is the tangent of 5e^x ?
The tangent of 5e^x is y=5e^{a_{0}}x+5e^{a_{0}}-5e^{a_{0}}a_{0}