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Popular >

area |x-2|,0=x-3y+6

Solution

area

∣ x - 2 ∣, 0 = x - 3 y + 6

Solution

8

Solution steps

Isolate

y

for

0 = x - 3 y + 6 : y = - \frac{- x - 6}{3}

Apply the area formula:

\int_{0}^{6} \frac{1}{3} (- x - 6) + ∣ x - 2 ∣ d x

Solve

\int_{0}^{6} \frac{1}{3} (- x - 6) + ∣ x - 2 ∣ d x : 8

The area is:

= 8

Popular Examples

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\int_{2}^{3} \frac{40}{3 - x} d x

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\frac{d}{d x} (\frac{cos ( x )}{1 + a sin ( x )})

integral of 6/(1+x^2)

\int \frac{6}{1 + x ^{2}} d x

limit as x approaches 1 of f(x)+g(x)

x \to 1 lim (f (x) + g (x))

sum from n=2 to infinity of n/(2n^2-3)

n = 2 \sum \infty \frac{n}{2 n ^{2} - 3}

Frequently Asked Questions (FAQ)

What is area |x-2|,0=x-3y+6 ?
The answer to area |x-2|,0=x-3y+6 is 8