What is derivative of f(x)=\sqrt[4]{t} ?

The answer to derivative of f(x)=\sqrt[4]{t} is (dt)/(dx)=0

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derivative of f(x)=\sqrt[4]{t}

derivative of

\frac{d t}{d x} = 0

Solution steps

Treat

t

t (x)

Differentiate both sides:

0 = \frac{\frac{d t}{d x}}{4 t ^{\frac{3}{4}}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

x \to \infty lim (x^{- 2} e^{2 x})

\frac{d}{d x} (e^{(2 x)^{3} - 2})

y^{^{'}} = \frac{( 4 t ^{3} + 1 )}{2 y - 6}

\int tan^{3} (x) sec^{2} (x) d x

y = 15 - x^{2}, y = x^{2} - 3

What is derivative of f(x)=\sqrt[4]{t} ?
The answer to derivative of f(x)=\sqrt[4]{t} is (dt)/(dx)=0